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Comment convertir rapidement la date en mots dans Excel?

En général, nous convertissons généralement la date en d'autres formats de date ou chiffres dans Excel, mais avez-vous déjà rencontré un problème concernant la conversion de la date en mots anglais comme illustré ci-dessous? En fait, il n'y a pas de fonction intégrée qui peut le gérer mais un code VBA.
doc date aux mots 1

Convertir la date en mot avec la fonction définie


Convertir la date en mot avec la fonction définie

Voici un code macro qui peut vous rendre service lors de la conversion des dates en mots.

1. Activez la feuille que vous utilisez et appuyez sur Alt + F11 clés pour ouvrir Microsoft Visual Basic pour applications fenêtre.

2. Cliquez insérer > Module et collez le code ci-dessous dans le script.

VBA: convertir la date en mot

Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Hundreds As String
    Dim Decades As String
    Dim xTensArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If
        Hundreds = Mid$(xYear, 2, 1)
    If CInt(Hundreds) Then
        Hundreds = xCardArr(CInt(Hundreds)) & " Hundred "
    Else
        Hundreds = ""
    End If
    DateToWords = xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  xCardArr(CInt(Left$(xYear, 1))) & _
                  " Thousand " & Hundreds & Decades
End Function

doc date aux mots 2

3. Enregistrez le code et revenez à la feuille, sélectionnez une cellule dans laquelle vous allez sortir le résultat, tapez cette formule = DateToWords (A1) (A1 est la date que vous utilisez), appuyez sur Entrer et faites glisser la poignée de remplissage automatique sur les cellules dont vous avez besoin. Voir la capture d'écran:
doc date aux mots 3


Nombres en mots

doc épeler le numéro 1

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Comments (23)
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This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST NINETEEN HUNDRED NINETY EIGHT
I need dob into words in upper format but i use this micros in excel i got this
07/08/1998 SEVENTH AUGUST ONE THOUSAND NINE HUNDRED NINETY-EIGHT which is not usefull
This comment was minimized by the moderator on the site
Hi, MAX, I have modified the VBA, please try and let me know if it works. Thanks.
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(CInt(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function

This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
This comment was minimized by the moderator on the site
Hi, try this vba:
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(Fix(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function

This comment was minimized by the moderator on the site
آپ کا بہت شکریہ
This comment was minimized by the moderator on the site
It is giving the #NAME? Error
This comment was minimized by the moderator on the site
I would like to add text to the output, for instance, 1958 gets converted to One Thousand Nineteen Hundred Fifty Eight and I would like it to say One Thousand Nineteen Hundred and Fifty Eight. Can someone give me an example of how I can do this please?
This comment was minimized by the moderator on the site
thank u for helping me . very useful in converting date of birth in word
This comment was minimized by the moderator on the site
Sir/Madam

It is very useful for me.

Really Amazing and helped to solve the problem within a minute.

Thank you for uploading this document. Very nice
This comment was minimized by the moderator on the site
how to use this code in vb6 for a textbox
This comment was minimized by the moderator on the site
date to word in gujarati language avilable ? please answer me. 9427909038
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I think it does not work for other languages except english.
This comment was minimized by the moderator on the site
Hello can we also do this in word docx?
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